A team has played 40 matches, winning 30% of them. If they win 60% of the remaining matches in a tournament, what will their total number of wins be? If they win 90% of the remaining matches, what will their total number of wins be?
Solution :-
A team has played 40 matches, winning 30% of them. Let the total number of matches in the tournament be T, and the remaining matches be R = T - 40.
Matches won so far: 30% of 40 = 12.
If they win 60% of the remaining matches:
New total wins = 12 + 0.6R
Given that their overall win percentage is 50%:
(12 + 0.6R) / T = 0.5
Since T = 40 + R:
12 + 0.6R = 0.5(40 + R)
12 + 0.6R = 20 + 0.5R
0.1R = 8 → R = 80
Thus, T = 40 + 80 = 120.
If they win 90% of the remaining matches:
Total wins = 12 + 0.9R = 12 + 0.9(80) = 12 + 72 = 84.
Answer: 84 matches.
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