An alloy contains p% silver by weight. A 100-gram piece of the alloy is added to it. After this, the new alloy is found to contain 90% silver by weight. If another 90-gram piece is added, the new alloy contains 84% silver by weight. Find the weight of the initial alloy.
Question Alloy Let the weight of the initial alloy be x , with p% silver by weight. For the first condition: (px + 100 * 3) / (x + 3) = 90 90(x + 3) = px + 300 90x + 270 = px + 300 px = 90x - 30 p = 90 - (30 / x) For the second condition: (px + 90 * 2) / (x + 2) = 84 84(x + 2) = px + 180 84x + 168 = px + 180 px = 84x - 12 Substituting p = 90 - (30 / x) : (90 - 30 / x)x = 84x - 12 90x - 30 = 84x - 12 6x = 18 → x = 3 Answer: 3 kg.